Define one newton and one dyne.
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One - gram mole of nitrogen occupies 2 × 10^4 cc at a pressure of 10^6 dynes/cm^2 . The average energy of a nitrogen molecule (in erg) will be: (Avogadro's number = 6 × 10^25 )
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A pressure of `10^(6)" dyne"//cm^(2)` is equivalent to : - YouTube
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One - gram mole of nitrogen occupies 2 × 10^4 cc at a pressure of 10^6 dynes/cm^2 . The average energy of a nitrogen molecule (in erg) will be: (Avogadro's number = 6 × 10^25 )
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SOLVED:If at a pressure of 10^6 dyne / cm^2, one gram mole of nitrogen occupies 2 ×10^4 c.c. volume, then the average energy of a nitrogen molecules in erg is : (Given:
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